deri 2

let f(x) = xk , k belongs to R.

the value of K so that f is differentiable (n-1) times at x=0, but not differentiable n-times at x=0 is:

a) n

b) n-1

c) (3n-2)/3

d) n.o.t.

tukka mari thi.. lag gaya tha.. par sahi method se koi try karo...

11 Answers

62
Lokesh Verma ·

if it is a polynomial it wont work

so it cant be a polynomial..

derivative of a polynomail remains a polynomial. (at the end it becomes zero!!)

So we have to think in terms of at best fractional terms

here the power will decrease by 1 on each differentiation..

so on n-1 derivatives, it will become...

x1/3 which will be zero at x=0 but its derivative will have -ve power of x! so it will not be defined!

62
Lokesh Verma ·

hence the answer is c) (3n-2)/3

think of a simpler example..

y= square root (x)

1
skygirl ·

no bhargav ans is not n-1.

bhaiya i din get you :'(

39
Dr.House ·

yup, i didtnt ssee, { at 0} sorry, thats why deleted my post

62
Lokesh Verma ·

@skygirl

a simpler question:

is √x differentiable at x=0??

what is its derivative?

62
Lokesh Verma ·

or
is (x)1/3 differentiable at x=0??

what is its derivative?

1
skygirl ·

@bhaiya,

shouldn it be n-2 ??

like u c,

for f(x) = x1 , f'(x) = 1 , f"(x) =0 ... further we get same value.

so its diff for upto 2nd derivative.

=> if k=n, its diff upto n+1 derivatives and not diff at n+2 th derivative

=> for not geting diferentiated at n, shouldn k be n-2 ??

1
skygirl ·

ok ok got you...

62
Lokesh Verma ·

:)

I did not say anything ;)

1
skygirl ·

hmm.. i blabbered...

got you... :)

thanx :)

1
skygirl ·

u said naa.... in post 2 and 3 [3]

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