Using Newton- Leibnitz theorem, we get
f(θ) = 1/1-cos2θ
Hence if y = f(θ)
Then, y = cosec2θ
y' = 2cosex2θcotθ
hence y'=2y√y2-1 is the de which is satisfied by the given function
NOT TOO SURE.......BUT JUST GAVE IT A TRY [4]
the function f(θ) = d/dθ∫0 θ dx/ (1-cos θcos x) satisfies wich diffrential equation ?
Using Newton- Leibnitz theorem, we get
f(θ) = 1/1-cos2θ
Hence if y = f(θ)
Then, y = cosec2θ
y' = 2cosex2θcotθ
hence y'=2y√y2-1 is the de which is satisfied by the given function
NOT TOO SURE.......BUT JUST GAVE IT A TRY [4]