divide by -1/y2 and then put 1/y = t
we get dt/dx + t.f(x)/f'(x) = 1/f(x)
now using integrating factor method it can be solved easily
Solve for y...
\frac{dy}{dx}=\frac{yf'(x)-y^2}{f(x)}
Is not as difficult as it looks?!
divide by -1/y2 and then put 1/y = t
we get dt/dx + t.f(x)/f'(x) = 1/f(x)
now using integrating factor method it can be solved easily