dx/dp=a(1+cosp)
dy/dp=asinp
dy/dx= sinp/(1+cosp)
sinp=2sinp/2 cosp/2
cosp+1=2sin2p/2
u get d ansewr
:)
if x=a(p+sin p),
y=a(1-cos p)
find dy/dx
ans=tan p/2
i m not getting it.pls help dosto...
dx/dp=a(1+cosp)
dy/dp=asinp
dy/dx= sinp/(1+cosp)
sinp=2sinp/2 cosp/2
cosp+1=2sin2p/2
u get d ansewr
:)
hey integration
cosp+1=2sin2p/2
Thus
dy/dx=(2sinp/2*cosp/2)/2sin2p/2
=(cosp/2)/sinp/2
=cotp/2
Anuj the Answer is cotp/2 and not tanp/2