1. (2x+a+b)(b-a) + 2 log (a+x)
(a+x)(b+x) (b+x)
[1]
3 Answers
skygirl
·2008-12-24 18:20:29
3. )
|y| <= x2
=> |y| - x2 <=0
=> y-x2 <=0 or -y -x2 <=0
=> y' <= 2x or y'>= -2x
=>|y'| <= 2x
3. )
|y| <= x2
=> |y| - x2 <=0
=> y-x2 <=0 or -y -x2 <=0
=> y' <= 2x or y'>= -2x
=>|y'| <= 2x