Calculus - Differentiate with respect to x,

1

see differentiation of sec^-1x = - x√1-x² and
differentiation of sin^-1x = 1√1-x²

use this property and chain rule ......
i thnk u will get ur answer

21

y=sec^-1x+1x-1+sin^-1 x-1x+1

= cos^-1 x-1x+1 +sin^-1 x-1x+1

=Î /2

so dy/dx=0

1

sec ^-1 x - 1x + 1 = cos ^-1 x - 1x + 1 , only when , -1 â‰¤ x - 1x + 1 â‰¤ 1 , whuch may not hold for any x .

1

but sibal is perfectly correct

1

no as gallardo mentioned
sibal is correct only when particular interval is mentioned

Differentiate with respect to x,