1u hv given the sol...........bt hw to solve it?........r we going to consider R constant here?
nd srry i hd put wrong 2nd option bt nw i hv corrected it
y2+x2=R2 and k=1/R,then k is equal to
a)IyI/√1+(y')2
b)Iy''I/√[1+(y')2]3
c)2Iy"I/√1+(y')2
d)Iy"I/2√(1+(y')2)3
also tell hw to solve
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27 Answers
11But still representing a constant in terms of variables is against logic, isn't it?
1
1sry ani i m too lazy to get that maths book whose location i dont know i will giv post it 2morow on ur scrap bt its frm the topic higher order differentiation u can easily find it
1357For any curve y=f(x)
k(curvature)=y''/(1+y'2)3/2
Radius of curvature R=1/k
for circle k=constant
1yup wat bhaiya is saying is correct & Q is from NCERT & now i dont thnk whole indian mathematicians r moorkh :D
1357given K is a general term for the curvature of a curve which is the inverse of radius of curvature.
Radius of curvature R=(1+y'2)3/2/y''
K(curvature)=1/R
Here in case of circle it is constant
11ratio can be a constant but who said it is. Abt the question setter i think u better ask honey.
1yup mr variable bt isnt it is the ratio & ratio can be constant & Q setter is not a moorkh i suppose :P
11A value which u can represent by variables is no longer a constant as it varies with variation in the variable :p
1see the options K is given in ratio ho sakta hai ki ratio const. rahe hamesha
also agar y chane karega to y' aur y'' bhi change karega
so i think in ratio they will like neutralize each others effect(kind of)
1i fully agree with aragorn..
wats the point of finding out a constant in terms of variables...
11k is a constant. But y' and y" are variables. So how can k be in terms of y' and y"?[7]
1u can clearly se that we dont want x, y in the result so diff it two times name them 1 , 2 now put value of y from 2 in 1 also put x from initial eqn in 1 u will get smethin in R,y',y''
so u can easily find K
11Honey said she got it from a book. She actually saw 2 questions. One is the question which posted as a test and the other one is this question.
1i can show it :D
i actually proved it bt i m really sure that something is seriously wrong with the options given
i m not actually getin opt b
11k is a constant. But y' and y" are variables. So how can k be in terms of y' and y"? [7]
1i don't know this ws the ques nd these options......i don't know hw to solve it
11R is a constant. It's the eqn of a circle with center at O and radius R
1if i knew i wldn't hv posted it here..........i m also confused bout the same thing:whether to tk R as cnstnt or nt coz if we tk thn it wld bcm 0 after differentiation
who hs said 'k' is constant