1eeeeeeeeeeeeeeeeeeee
used to do it...
bachpan me [3]
6 Answers
62cos-1x2
lim (cos-1(x+h)2 - cos-1x2)/h
h->0
Apply some small tricks... that is all!
Similar for others... might seem that i have said the obvious.. but sometimes you have to do the obvious ;)
62may be trick is not as appropriate a word as manipulation wud have been ;)
1hey i got something!!
lim (cos^-1(x+h)^2 - cos^-1x^2)/h
h->0
take cos-1x2 = t => x2 =cost
again, cos-1(x+h)2 = (t+Δt)
now,
cos-1(x+h)2 - cos-1x2 = Δt
and, h = √cox(t+Δt) - √cost
now apply nishant bhaiya's formula ...
