differentiation...........

IIT JEE Tutorials › Calculus questions › differentiation...........

let tanÎ¸= limx-0(cosx+sinx/cosx+sinx.cosx)^{cosecx} then, Î¸=?

a)pi/2 b)pi/3 c)pi/6 d)pi/4

#Mathematics #Calculus

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6 Answers

1

Akand ·2009-03-17 07:51:39

pi/4 dude...............wait il post d solution........

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Akand ·2009-03-17 07:53:42

tanÎ¸=e^{(cosx+tanx+sinxcosx-1)cosecx}
=e^{(tanx+sinx)/sinx}
=e²..............wat d heck sorry made a msitake

wel ok.......
=e^{(tanx+sinx)/sinx}
=e^{(tanx+sinx)cosecx}
=e⁰
=1

so pi/4........

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rahul nair ·2009-03-17 08:14:23

hey dude, post the soln.. soon

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Optimus Prime ·2009-03-18 00:12:45

limâ†’0 (cosx+sinx/cosx+sixcosx)^cosecx

limâ†’0 (1+ sinx-cosx/cosx+sinxcosx)^cosecx

e^{limâ†’0 (sinx-sinxcosx/cosx+sinxcosx)cosecx}

e⁰= 1

tanA= 1

A= pi/4

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Lokesh Verma ·2009-03-18 00:42:41

Great work Amit :)

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Optimus Prime ·2009-03-18 00:46:46

thanks

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω