hey.....f '(xy) is a non-zero constant at (4,2)
is this a DONKEY's toil - work Question Or has some more Elegant - Plausible Approach to it ?? [7]
-
UP 0 DOWN 0 1 11
11 Answers
rkrish
·2009-04-02 23:38:52
Did not solve completely.....but....
try putting xy = θ
So, (θ,y) ≡ (8,2)
Convert the entire thing to sin & cos.
I dont it'll help much.
Manish Shankar
·2009-04-02 23:40:52
let it be f(xy)=14
differentiating wrt to y
f'(xy)[(y+xdx/dy]=0
this might help
rkrish
·2009-04-02 23:56:24
@tapan...
f'(xy)[ydx/dy+x]=0
implies ydx/dy + x = 0
So, dx/dy = -x/y = -2
@ richa....ques is find dx/dy
tapanmast Vora
·2009-04-02 23:57:37
oh k kk..... now i got y RK said f'(xy) ≠0
Yeah then it gets much SIMPLER.....