3f(f-1x)=x
u have option use the option to check.
Let f:(4,6)--> (6,infinity) be a funtion defined by f(x) = x +[x/2], where [] is GIF.Then f-1(x) =
a. x-[x/2]
b.-x-2
c.x-2
d. NOT
How to find the inverse of such funtions involving GIF, fractional part etc..
And soln and explanation for above Q
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7 Answers
11the basic thing to be kept in finding the inverse of the function is
To find the inverse of f(x) u have to find it mirror image in y=x
So u have to draw the graph of x+[x/2]
i think u can proceed now !!!!
1from (4,6) we have, [x/2]=2
so the function is x+2 in the given domain,
f(x)=x+2
or finverse(x)=x-2,
so C)
cheers!!
1k...what is the other method than graphical one mani...i also need algebric method
9Q is actually wrong
f-1(x) doesnt exist as range ≠codomain
so ans is d ( NOT )
pls confirm sri