doubt

i have done upto this ,solve after this. i am not getting the ans

x = y²t

Differentiating wrt x on both sides

1 = 2y dy/dx t + y²dt/dx

=>1 - dy/dx 2yt = y² dt/dx

=>dy/dx = [ 1-y²dt/dx ]/2yt

So , 1 - y²dt/dx = 2y²t/y²(1-t)

=> integ [ 1-t/t(1-3t) ] dt = integ [ 1/x] dx

=>2 ln (1-3t) + ln t = ln x + c

=> ln (1-3t)²t = lnx + c

manish , express that as funtion of y

@Nishant Sir i editted the solution!!! : )

yes,i also couldnt understand dat.......