341Two queries?
1) Did you mean to write:
\int_0^{2[t+14]} \left\{\frac{x}{2} \right\} dx = \int_0^{\left\{t \right\}} [x+14] dx and to solve for t.
2) edited: are the answers: -14, -13/2, -78/7, -169/14?
find the value of x satisfying
\int_{0}^{2[x+14]}{\left\{\frac{x}{2} \right\}}dx=\int_{0}^{\left\{x \right\}}{\left[x+14 \right]}dx
wer [.] is gif and { } fractional part of x
this is an easy one but my ans not matching[2]
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7 Answers
341
1no not for t......Q says the value of x satisfying the given eq
ans is [-14,-13)
1in the answer its given interval of x in which it is lying that is [14,-13) not specific values of x [7]
62\\\int_{0}^{2[t+14]}{\left\{\frac{x}{2} \right\}}dx=\int_{0}^{\left\{t \right\}}{[x+14]dx} \\\Rightarrow \int_{0}^{2[t]+28}{\left\{\frac{x}{2} \right\}}dx=\left\{t \right\}[x+14]dx \\\Rightarrow t+14]=\left\{t \right\}[t+14]dx
assuming that what you are saying indeed means what is correct (ie what prophet sir has written)
then,
so , [t+14]=0
so t lies in [-14, -13)