f(1)=???????????

f is a real valued function satisfying

1 Answers

I think this one has been solved a few times here

but still

|f(x+h)-f(x)| <= (x+h-x)²

thus, take the definitoin of limit, you get

|f(x+h)-f(x) / h| <= |h|

dividing both sides by |h|

now take limit h - > 0

you get f'(x) = 0 for all x

thus, f(1) = f(0) = 0

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