\hspace{-16}$If $\mathbf{f(0)=1}$ and $\mathbf{f(1)=2}$ and $\mathbf{f(x)=\frac{f(x+1)+f(x+2)}{2}}$\\\\\\ Then $\mathbf{f(2012)=}$
f(x) = 1/3.[4-(-2)x]
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\hspace{-16}$If $\mathbf{f(0)=1}$ and $\mathbf{f(1)=2}$ and $\mathbf{f(x)=\frac{f(x+1)+f(x+2)}{2}}$\\\\\\ Then $\mathbf{f(2012)=}$
f(x) = 1/3.[4-(-2)x]