3/2*(√x)∂x=∂t
(√x)∂x=(2/3)∂t
and.... x3=t2
now, I think U can solve it....[6]
3/2*(√x)∂x=∂t
(√x)∂x=(2/3)∂t
and.... x3=t2
now, I think U can solve it....[6]
i have got one more method
check if it is correct
integration of numerator is 2x3/2/3
so let x3/2=t 3/2 x1/2dx = dt
∫x1/2/√(X3/2)2+(a3/2)2
=∫2/3dt / √t2+(a3/2)2
= 2/3 ∫dt/√t2+(a3/2)2
=2/3 log|(t+√t2+(a3/2)2)|
= 2/3 log|x3/2+√x3+a3|
is it correct nishant sir?