find::::

sum of the series
\frac{1.2}{3!}+\frac{2.2^2}{4!}+\frac{3.2^3}{5!}+............\infty

3 Answers

341
Hari Shankar ·

t_n = \frac{n.2^n}{(n+2)!} = \frac{2^n}{(n+1)!}-\frac{2^{n+1}}{(n+2)!}

and you have a telescopic summation

1
Che ·

oh yes....thanks.

1
Che ·

btw @numb ans is not 3-e

its 1

Your Answer

Close [X]