1keep aside the limits for now...
the integration is basically...I = dx/((1+√x)√x(√1-x))
so
take 1+√x=t.
=> dx/2√x=dt.
=> dx/√x=2dt.
then,
√(1-x)= √(2t-t2)
so the integration boils down to a std. form......
I= ∫2dt/ t√(2t-t2)
here, put t=1/z. and u can easily solve...
then put limits....
