function89

f(x)=mod(modx-1) find f'(x)

6 Answers

62
Lokesh Verma ·

Hint: draw the graph

The slope will either be 1 or -1 other than at critical points...

Give it a shot

3
rocky ·

not getting

62
Lokesh Verma ·

what is the value of the function at x=-1, x=1, x=0

will there be another point where the shape of the graph changes?

3
rocky ·

no

1
aieeee ·

also,if we draw the sign scheme of f(x) we will find four intervals and their values would be:
f(x)= (x-1) when x belongs to (1,∞)
= -x+1 ,when x belongs to (0,1)
= x-1 ,when x belongs to (-1,0)
= -x-1 ,when x belongs to (-∞,-1)
sumeet, hope now u cn find f'(x) in d respective intervals

62
Lokesh Verma ·

One simpler method

Draw the graph of |x|

then Think of |x|-1

Then draw the graph of ||x|-1|

Then it is trivial :)

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