yeh toh constant function ho jaega...
so f(2) = 10 => f(x)=10
and hence f(1.5)=10
let f:R-->R is a continous function on [1,3].let f(x) takes rational valeus for all x.if f(2)=10.f'(2)=0.find f(x) and f(1.5)
yeh toh constant function ho jaega...
so f(2) = 10 => f(x)=10
and hence f(1.5)=10