COMPREHENSION
let f(x) and g(x) are two distinct functions such that f(x) is an odd function and g(x) is an even function for all X ε R . Let a function h(x)=f(x) +g(x) is an odd function and φ(x)=f(g(x))+g(f(x)).
NOW ANSWER THE FOLLOWING QUESTIONS (1-%):
1. Function g(x) is
(a) a trigonometrical function (b) a polynomial function
(c) an absolute function (d) a constant function
2. The number of solutions of f(x)= g(x) is
(a) 1 (b) 2
(c) 0 (d) 3
3. The behaviour of h(x) for all x ε R IS
(a) An increasing function (b)a decreasing function
(c) a constant function (d) nothing can be said
4. The number of solutions of φ(x) = h(x) is
(a) 2 (b) 1
(c) 0 (d) 3
5. For the functions h(x) and φ (x)
(a) h' (x) > φ'(x) (b) h' (x) < φ'(x)
(c) h'(x) ≤ φ'(x) (d) nothing can be said
MULTIPLE CHOICE
7. if f(x) is a polynomial of degree 5 with real coefficients defined for real x such that f(|x|) = 0 has 8 non-zero real roots then f(x) =0 has
(a) 4 positive roots (b) 1 negative root
(c) 5 real roots (d) at least two imaginary roots
11. Let : R→R be defined by f(x) = x2 +ax+1/x2+x+1. The set of exhaustive values of a such that f(x) is onto is
(a) (-∞,∞) (b) (-∞,0)
(c) (1,∞) (d) φ
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31 Answers
7. if f(x) is a polynomial of degree 5 with real coefficients defined for real x such that f(|x|) = 0 has 8 non-zero real roots then f(x) =0 has
(a) 4 positive roots (b) 1 negative root
(c) 5 real roots (d) at least two imaginary roots
Part 7 is simple.. this will have 4 +ve and 4 -ve roots.. hence no imaginary roots... and in all 5 real roots including zero... (zero will be a root for sure!) Can you complete the logic for this part?
All bakwas