**Functions **

13) Period of the function f(x) = sin{sin(∩x)} + e(3x) , where {.} denotes fractional part, is

a)1

b)2

c)3

d)6

14)The min values of the function f(x) = {sin-1(sinx)}2 - sin-1(sinx) is

a)∩/4(Π+ 2)

b)Î /4(Î -2)

c)Î /2(Î +2)

d)Î /2(Î - 2)

16) f(x) = (ax + b)/(cx +d ) , Then for allowable values , fof(x) = x provided that

a) d = -a

b)c = b

c)a=b=1

d)all of these

19) f(x) = x3 + 3x2 + 4x + bsinx + c cosx for all x ε R is a one - one function ,
then the greatest value of b2 + c2 is

a) 1

b)2

c)21/2

d) NONE

20) If 2< x2 < 3 then the no. of +ve roots of {1/x} = {x2} , where {.} denotes the fractional part of x is,

a)0

b)1

c)2

d)3

9 Answers

1
archana anand ·

16)A)d=-a
14) B..

4
UTTARA ·

@Archana : 20 ) ans B

16 ) A, but i was getting all the options true check out once again

14 th Qs is correct ∩ stands for pie (if u dint understand here)

1
archana anand ·

for 16 option A is neccesarily and sufficiently true......and u cant get c to b true

4
UTTARA ·

19 ) ANS A

16 ) A

20 ) B

106
Asish Mahapatra ·

19) f(x) = x3 + 3x2 + 4x + bsinx + c cosx for all x ε R is a one - one function ,
then the greatest value of b2 + c2 is

If it is one-one,
f'(x) = 3x2+6x+4+bcosx-csinx
will have same sign.

Now min. value of 3x2+6x+4 = (4.4.3-36)/4.3 = 1

So, for f'(x) to be +ve always,
min value of bcosx-csinx = -1
this is when b2+c2 = 1

106
Asish Mahapatra ·

20

24
eureka123 ·

20
Without graph

y={1/x} is continuous and differentiable for all x ε(√2.√3)
=>dy/dx=-1/x2 which is less than zero for all x>0
=> Monotonically decreasing

y={x2} is alos continuous and differentiable in region (√2.√3)
dy/dx=2x which is greater than zero for all x>0
=> Monotonically increasing

Since these 2 curves are monotonically inc .and dec. respectively
so they must intersect only once in the region

24
eureka123 ·

13
is answer 2 ??

4
UTTARA ·

13 ans is d) 6

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