1how i can i apply it in dis question!!!
Domain of the explicit form of the funtion y represented implicitly by the equation, (1+x)cos y - x2 = 0 is:
a. (-1, 1]
b. (-1, (1-√5)/2]
c. [(1-√5)/2, (1+qrt]5)/2]
d. [0, (1-√5)/2]
plz explain the meaning of explicit and implicit form!!!
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4 Answers
11when a function is of the form
y = f(x) ---- it is an explicit function
when it is of the form
f(x)+f(y) = k , it is an implicit function
106u convert the eqn to the form y=f(x) ..here cosy = x2/(x+1) ==> y = cos-1(x2/(x+1) )
For domain of this function,
-1 ≤ x2/(x+1) ≤1
So, the two inequalities are x2+x+1 ≥0 (always satisfied)
and x2-x-1 ≤0
So, x shud lie between the roots [(1-√5)/2, (1+√5)/2]