give me graph only....

AIEEE 2015 Preparation › Calculus questions › give me graph only....

f(x)=x²-4x
g(x)=min f(t) ; xâ‰¤tâ‰¤x+1 ; 0â‰¤x<4

i know this type ahs been discussed before...but i just need graph to check myself....no calculations....[1]

#Mathematics #Calculus

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7 Answers

62

Lokesh Verma ·2009-12-27 08:08:24

Another awesome one... no one game?

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24

eureka123 ·2009-12-27 09:56:08

here is my answer..confirm if its rite or not

g(x)= f(x+1) x+1<2
-4 1<x<2
f(x) xâ‰¥2

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1

akari ·2009-12-27 10:51:34

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66

kaymant ·2009-12-27 20:50:10

@eureka
You g(x) defined in #3 is okay.

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1

akari ·2009-12-27 20:56:37

anant sir is my graph wrong ?

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66

kaymant ·2009-12-27 21:20:53

yes akari, your graph is not correct. There is an interval when g(x) is a constant.

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SANDIPAN CHAKRABORTY ·2009-12-31 05:32:18

solving f(x) i am getting (y+4)=(x-2)^{2
so graph of f(x) is an upward opening parabola with vertex at (2,-4)
next how to proceed?
how to find g(x)}

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

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° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω