9 Answers
Optimus Prime
·2009-03-29 05:34:53
no dude u are rite
but some part of ur graph can be rite if u mention the points
Mani Pal Singh
·2009-03-29 05:37:03
i think the graph from 1,2 needs a lot of attention
BUT I CLEARLY MENTIONED IT IS A ROUGH SKETCH!!!!!!!!!
Lokesh Verma
·2009-03-29 06:24:52
mani.. if you took the mirror image and your graph.. then you wud have the right answer
think more closely :)
Kalyan Pilla
·2009-03-29 08:35:31
C'mon yaar
Y wud sum1 need a graph plotter 4 dis???
y2≥0
ie., f(x)=(x-1)(x-2)(x-3)≥0 This is true only when x→[1,2]U[3,∞)
f(x) increases beyond x=3 as all three (x-1),(x-2) and (x-3) increase and the product is bound to increase.
So it increases beyond 3
f"(x)<0 inx=[1,2]
So we get one part of the graph.
here y=√y2 =/y/
Therefore,
Image of graph is replicated about x axis