Gud area...lets see whether u can calculate it

1)FInd area bounded by mod(y)=e-mod(x) with [mod(x)+mod(y)]/2 + [mod(x)-mod(y)]/2 ≤2

2)Find area of region at point P satisfying maximum{PA+PB,PB+PC}<2 where A=(1/2 ,0) ,B=(3/2 , 0) ,C=(5/2 , 0)

68 Answers

21
tapanmast Vora ·

Okie....

thn i'l go ahaed wid other cases too

62
Lokesh Verma ·

yes it seems correct to me :)

21
tapanmast Vora ·

Yah Sir, can u pl. chk my approach for 1<x<2 coz i m not fully sure in dat one!
rest shall b eezie

21
tapanmast Vora ·

Oh yes Sir, it wud b pretty easy...... I jus wanted to know if My approach in #10 is Bingo or [2]

21
tapanmast Vora ·

yehe!!!!

ANS : Î /√3 - 3/4

ELLIPSE is the biggest HINT!!!!!

EXPERTS PL. AFFIRM MY ANS if its rite.......

21
tapanmast Vora ·

yah!!!

this graf is true.....

wich 2nd curv are u tokin abt?

11
Mani Pal Singh ·

Q1
TAPAN BHAI 1ST CURVE KO TO BANANA ASSAN HAI BUT 2ND CURVE MUSHKIL HAI
1ST CURVE WILL LOKE LIKE AS SHOWN
LETS WORK ON 2ND CURVE TO FIND THE AREA

21
tapanmast Vora ·

mani thats 4 da outer boundary of ellipse wer equality occurs..... ALL AREA WITHIN THAT AREA WILL OBVIOUSLY OBEY THE INEQUALTY...... [12]

21
tapanmast Vora ·

lets take jus 1st quad rite now....

y>,x>0

y = e^-x

[x + e^-x] + [x - e^-x] = 4

CMON GUYZ HELP ME FIND x frm abov equation baki sab ho jaega......

11
Mani Pal Singh ·

tapan u said
THINK ELLIPSE........................... SUM OF DIS OF A POINT FRM 2 POINTS IS A CONST. QUANTITY!!!!!!!
but its inequality given?????

11
Mani Pal Singh ·

hey
tapan work on the the 1st ques till the end
itd not that easy
try to find the exact answer rather than the method

21
tapanmast Vora ·

no reply [2]

no answers [2]

21
tapanmast Vora ·

this is my ruf working for que2....... IF IT MAKES SENSE TO U [3]

21
tapanmast Vora ·

par yeh eqtn to solv kar do pehle jee : [x + e^-x] + [x - e^-x] = 4

21
tapanmast Vora ·

HEy guyzzzzzz

Eureka dusnt hav the answers 4 this un.......

Pl. post ur answers so v can discuss, ie 4 QUE2

21
tapanmast Vora ·

Q2 mein progress ho raha hai.......... shayad ho jaega.......

21
tapanmast Vora ·

Q2 : THINK ELLIPSE........................... SUM OF DIS OF A POINT FRM 2 POINTS IS A CONST. QUANTITY!!!!!!!

21
tapanmast Vora ·

HOPE U GOT Q1

now lemme try Q2.......... looks interesting!!

21
tapanmast Vora ·

ROUGH SKETCH BANA : QUESTION WILL B MORE CLEAR.........

graf will b symm abt both da axis.......... baki to simple e^-x,e^x,-e^x,-e^-x for each of the QUADRANTS banega..........

now can u see ur defiite integeration ans ready.........

jus apply the limits as per da question.............

OR

maybe apply for jus 1 quad and 4times the answer as it will be same in all 4

39
Dr.House ·

yes tapan that is GIF

21
tapanmast Vora ·

yeh kyu untuchd hai??

eureka did u get da ans or wat??

btw does [.] in the question represent GR8est integer function???

11
Mani Pal Singh ·

dont waste time on gving the values
try to plot it and find the area!!!!!!!!!!!!

24
eureka123 ·

no thats not GINT..........simple brackets

21
tapanmast Vora ·

then to answer is VERY simple

ANS = 4 * (1 - e^-2)

ans = 3.45865

11
Mani Pal Singh ·

tapan yaar hum ne uska area bounded nikaalna hai!!!!!!!!!1
but wat is "t"

21
tapanmast Vora ·

IF THATS NOT THE CASE NA TO MEIN kal mathie ki baddie service karne vala huun

21
tapanmast Vora ·

jus chk usin CAlc. u'll get it. HOPE [.] denotes gr8est integer function in ur question

21
tapanmast Vora ·

arre mani. graf plot karke tujhe pata kab chalega ki last value of x wich satisfies the hot-discussed equation......

tera graf sahi hai..... u need to intgrat y = e^-x frm 0 to t and thn multiply it by 4 and the sum is done.... but that "t" is very imp

24
eureka123 ·

i could wrong also tapan.......[2]

24
eureka123 ·

wont they cancel out???????
e^-x

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