1gud bhaiyya
4 Answers
62T(x) = 1/2. {2 sin (x/2)}2 . tan (x/2)
S(x) = x/2 - 1/2{2 sin (x/2)} cos(x/2)
The limit of T(x)/S(x) = 0
Check the first two expressions for mistakes :)
24can u plz elaborate sir........
i think there is some mistake in T(x)...........
1T(X) = area of the triange..
that will be base. height /2
base= PQ = 2. sin (X/2)
< PQR= x/2
Height = PQ/2 tan X/2
So area will be 1/2. PQ. Height..
I think u are right.. the area will be half of what is wrote above..
Pls check if this method works or I have made more mistakes.