Have I commited any mistake????

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QIf the tangent to the curve y=f(x) forms angle pi/3 and pi/4 with X axis at points x=a and x=b respectively then evaluate
a to b âˆ« f'(x)f" (x) dx

My method:::
Integating by parts taking f'(x) as first function ,
I =[f '²(x)]_a^b- âˆ«f " (x).f ' (x)
=>2I= f '²(x)
=>2I = ( f '(b) - f '(a) )²

#Mathematics #Calculus

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6 Answers

Lokesh Verma ·2009-03-08 07:48:04

=>2I = ( f '(b) - f '(a) )²
this is wrong

it should be

=>2I = ( f '(b) ²- f '(a)²)

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Abhishek Priyam ·2009-03-08 07:48:43

>2I = ( f '(b) - f '(a) )²

[3]
>2I = ( f '(b))² -( f '(a) )2

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Abhishek Priyam ·2009-03-08 07:49:29

same time...

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eureka123 ·2009-03-08 07:59:06

sharamnaak galti.................[2][2][2][2]

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Lokesh Verma ·2009-03-08 08:00:59

no probs..

hota hai ;)

havent u seen my mistakes on the forum ;)

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eureka123 ·2009-03-08 08:03:16

sir aap to bade hain........aapko aur bhi kitne saare kaam hain........mujhe to bahut kam cheezon ka dhyan rakhna hai aur usme bhi agar galti ho to dukh hota hai........[2][2]

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∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

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Have I commited any mistake????

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