f(x) is a discontinous function only at x=0 such that ( f(x) )2=1 for all values of x ε R , then the numbers of such functions is :
A. 3
B. 2
C. 6
D. 4
Actually i am getting it as 4 but the answer given is 6 .... now is the answer wrong or am i not getting the other two such functions !!
the functions that i could make out are :
1. for all x ε R - , f(x) = -1 ; for x=0 ,f(x)=-1 and for all x ε R+ ,f(x)=1
2. for all x ε R- ,f(x)=-1 ; for x=0 ,f(x)=1 and for all x ε R+ ,f(x) =1
3. for all x ε R-, f(x) =1 ; for x=0 , f(x) =1 and for all x ε R+,f(x)= -1
4. for all x ε R- ,f(x)= 1 ; for x=0 , f(x)=-1 and for all x ε R+ , f(x) = -1 please help
9my intuition is that u ve typed Q wrongly
it shud read as
f(x) is discontinou only at x=0 such that ( f(x) )2=1 for all values of x ε R , then the numbers of such functions is :
A. 3
B. 2
C. 6
D. 4
now
R+,R- and 0 can have ±1
ie 2X2X2 =8 functions
of these f(x)=1 and f(x)=-1 are continuous always
so req = 8 - 2 =6
1hi celestine ... which are the other two whuch i have missed out there?
15. for all x ε R- ,f(x)= 1 ; for x=0 , f(x)=-1 and for all x ε R+ , f(x) = 1
6. for all x ε R- ,f(x)= -1 ; for x=0 , f(x)=1 and for all x ε R+ , f(x) = -1