indefinite Integral (3 june)

BITSAT 2015 Discussion Forum › Calculus questions › indefinite Integral (3 june)

\hspace{-16}\bf{\int\tan^{2}(x).\sin^{-1}(\tan x-x)dx}

#Mathematics #Calculus

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1 Answers

262

Aditya Bhutra ·2012-06-07 07:17:29

tanx - x = t

(sec²x -1 )dx = dt

tan²x dx=dt

then using integration by parts finishes the problem.

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