∫sin(100x+x)sin100-1xdx=∫sin100x sin100x cosx/sinx+ sin100x cos100x. dx=I1+I2.
integrating I2 by parts ,we get
sin100x sin100x/100 - I1
∫sin(100x+x)sin100-1xdx=∫sin100x sin100x cosx/sinx+ sin100x cos100x. dx=I1+I2.
integrating I2 by parts ,we get
sin100x sin100x/100 - I1