sin2x=2sinxcosx
take cosx=t
then sinxdx=-dt
apply byparts...
∫e^t . 2t.(-dt).
In such problems where the two fns involved can't be represented in each other terms like ex and sin(2x) Integration by parts is helpful.
Now U can do it...........
sin2x=2sinxcosx
take cosx=t
then sinxdx=-dt
apply byparts...
∫e^t . 2t.(-dt).