7/5*(x-2/x+3)power1/7
15 Answers
kamalendu ghosh
·2009-03-16 07:22:20
Take {(x-2)/(x+3)}^(6/7) as t {(x-2)/(x+3)}^(6/7)*(x+3)2 is the denom. u will get ∂t=(5)/(x+3)2 there fore the integ is.. 1/5∫∂t/t^(6/7)
Abhishek Priyam
·2009-03-16 07:29:05
correct answer or expalantion or good question... or helpful posts...