1Please give the solution also :-(
\int_{0}^{\infty}{e^{-x^2}dx}=\sqrt{\frac{\pi }{2}}
then find value of \int_{0}^{\infty}{e^{-ax^2}dx},a>0
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3 Answers
106Hint: use
if ∫f(x)=g(x)+c, then
∫f(ax+b) = 1ag(ax+b) +c
Solution:
ax2 can be written as (x√a)2
So the answer will be
1√a√∩√2