look shriya
multiply and divide by a
u know that
if
p=-ax3
then dp=-3ax2dx
so substitute these values and now integrate
-1/3a ∫epdp
-1/3a X e-ax3...................ANS
find out ∫ x2 e-ax3 dx actually i have to use this integration to solve a question of physics i haven't yet, gone through calculus so please dont give any direct solution . it would be better if you use any kind of substitution for solving this one....... please!!
look shriya
multiply and divide by a
u know that
if
p=-ax3
then dp=-3ax2dx
so substitute these values and now integrate
-1/3a ∫epdp
-1/3a X e-ax3...................ANS
thank you
i got the method !
we have x2dx=-dp/3a
so
( -1/3a) ∫(epdp
so we have -e-ax3/3a...ans
please check it out