integration !!

find out ∫ x2 e-ax3 dx actually i have to use this integration to solve a question of physics i haven't yet, gone through calculus so please dont give any direct solution . it would be better if you use any kind of substitution for solving this one....... please!!

3 Answers

11
Mani Pal Singh ·

look shriya
multiply and divide by a

u know that
if

p=-ax3
then dp=-3ax2dx
so substitute these values and now integrate

-1/3a ∫epdp

-1/3a X e-ax3...................ANS

1
Shriya ·

thank you
i got the method !
we have x2dx=-dp/3a

so

( -1/3a) ∫(epdp

so we have -e-ax3/3a...ans

please check it out

1
Shriya ·

ok thank you :)

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