integration3

3 Answers

1357
Manish Shankar ·

show your steps here

4
UTTARA ·

Put 1-x = t2 => - dx = 2t dt

I = -2 { integ [ dt / ( √1-t2) ( 1 + √1-t2) ] }

Put t = sinθ

=> dt = cosθ dθ

I = - INTEG [ sec2θ/2 dθ ]

= - 2tan θ/2

39
Dr.House ·

last step will answer will be -2 tan θ/2

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