first term = 5-2pi
2nd term = 2pi-6
3rd term = 7-2pi
thus k-2pi = (5-6+7) - 2pi
k=6
for the principal value of sin-1(sin5)+cos-1(cos6)+tan-1(tan7)=k-2Ï€
find the integral value of k
it is silly b ut its a doubt......
first term = 5-2pi
2nd term = 2pi-6
3rd term = 7-2pi
thus k-2pi = (5-6+7) - 2pi
k=6