limit 3

lim (√1-√sin2x)/Î - 4x
x->Î /4

3 Answers

62
Lokesh Verma ·

Thankfully, there is a simpler workout :)

find

lim (1-√sin2x)/(Î -4x)2
x->Î /4

now take square root of this whole thing..

1
°ღ•๓яυΠ·

u can also do like let h=x-pi/4
werin h-->0
so that guy is basically
lim(h->0)(√1-√cos2h)/4h
nw itz zero on zero apply l'pithal

62
Lokesh Verma ·

good soln :)

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