or, put logx=t
or we have
limx→∞ (1+et+e2t)/t3
= [1+(1+t+t2/2+t3/6+...)+(1+2t+2t2+8t3/6...)]/t3
=3/t3 +3t/t3 + 5t2/2t3 + 3/2 + (powers of t more than 3)/t3
=∞
cheers!!
apply LH rule...
1+2x3(ln x)2 1x
= x+2x23(ln x)2
again apply LH rule
= 1+4x6(ln x)/x
= x+4x26(ln x)
= 1+8x6/x
= x+8x26
which seems to be infinite !
or, put logx=t
or we have
limx→∞ (1+et+e2t)/t3
= [1+(1+t+t2/2+t3/6+...)+(1+2t+2t2+8t3/6...)]/t3
=3/t3 +3t/t3 + 5t2/2t3 + 3/2 + (powers of t more than 3)/t3
=∞
cheers!!