limit

Q1. find the limit
lim(x→0) (1+x)1/x-e+(ex/2)x2

Q2. Let the rth term tr of a series be given by tr = r1+r2+r4. Then find the value of lim(n→∞) Σtr (n=1 to n=n)

Q3. If x is a real number in [0,1]. Then the value of lim lim [1+cos2m(n!Î x)]
(m→∞)(n→∞)

5 Answers

11
Mani Pal Singh ·

Q1 lagao expansions or
u know that (1+x)1/x=e when limit x->0
u got ex/2x2
now check the question
something missing

106
Asish Mahapatra ·

actually the Question says 2 prove that the limit is 11e/24
par mera aa rahaa tha lim does not exist..

11
Mani Pal Singh ·

have u tried expansions

66
kaymant ·

2) Transform tr as
tr = 12 . 2r(r2 + r +1)(r2 - r + 1) = 12 . (r2 + r +1) - (r2 - r + 1)(r2 + r +1)(r2 - r + 1)
=12 (1r2 - r + 1 - 1r2 + r + 1 )

Now the sum telescopes to give

Sn = 12 (1 - 1n2 + n + 1 )

So as n → ∞, Sn → 12

24
eureka123 ·

Q3 is very standard...
it was solved by nishant sir here..
http://targetiit.com/iit-jee-forum/posts/area-262.html?dpid=1522[1]

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