1well i also firstly though it lik that....but u know wat.....x here is tending to 0...not 0....so x must hav some value which is in the neibourhood of 0 so x2/2 has some value
(we can ignore higher poers since they r tending to 0) so 1-x2/2 is always less than 1 weh x tends to infinity
so [1-x2/2....]=0
