limit -trigo

i got 3/2 . please verify .

turned sec into cos and applied LH rule to the fraction two times.

yes...the answer is 3/2....its becoming simpler by not applying l hospitals rule!!

my trick but do not memorise

\lim_{x\rightarrow 0}\frac{sec ax - sec bx}{seccx - sec dx} = \frac{a^{2}-b^{2}}{c^{2}-d^{2}} :)

yup...!!

the answer is 3/2.