1 Answers
Lokesh Verma
·2009-07-29 00:19:32
lim n->0 f(1+n)n = 5
lim n->0 f(1+n)n-f(1)n = 5-f(1)/n
lim n->0 f(1+n)-f(1)n = 5-f(1)/n
for the derivative to exist, lim n->0, f(1)/n has to be 0
and hence derivative is given by
lim n->0 f(1+n)-f(1)n = 5
thus, the derivative is 5