limits

yes all the three exist...
1) -2
2) ∩/2
3) 1

lim_x→-1 sin^-1x also exists ,and the limit is - π/2

ya
rite
all of them exist...

:)

@Querty But lim_x-->-1(-)sin(inverse x) doesnt exist, i.e LHL doesnt exist as it is not in the domain of sin(inverse x).

x→ -1⁺ is in domain
x→ -1^- isnt in domain itself

so wen we are taking limit x→ -1, we consider x→ -1⁺ only

u draw graph of sin^-1x , and see wat does sin^-1x tend to wen x tends to -1