39Limit is undefined....
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Left Hand Limit
Limx→(0-)e-1/xx
= Limh→0e1/h-h
Right Hand Limit
Limx→(0+)e-1/xx
= Limh→0e-1/hh
Clearly LHL ≠RHL, and hence the limit does not exist.
\lim_{x\rightarrow0}\frac{e^\frac{-1}{x}}{x}
I Cannot Solve it !
I Even Dont Know The Answer !
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3 Answers
39
1Thanks
But It Does not have a particular limit in any side rhl or lhl !!
That's where i was confused.
39The LHL is -∞/0 and the RHL is 0/0. Infinitely Irremovable Discontinuity.