i didnt know the answerfor the question. Can u have the prooof.
i have managed to get the same answer by equating the numerator and denominator.I want to check its correctness.
i didnt know the answerfor the question. Can u have the prooof.
i have managed to get the same answer by equating the numerator and denominator.I want to check its correctness.
aplying limits separately for numerator and denominator
we get Lt(x-4)f(X)=7
i just guessed it may be any funtion satisfying this value
so gave f(x)=x+3
not sure abt the mthd
Denominator is not tending to zero so numerator must not be zero and should be finite.. therefore
Lt f(x)=7
x→4
So any function satisfying this can be f(x)
Better see options and carefully as it may be multiple correct..
examples of f(x)=x+3
or
f(x)=7
or
f(x)=sin(xÎ /8)+6
or
..
or
..
or
..