anyone..reply.......
3 Answers
dimensions (dimentime)
·2009-01-22 02:11:33
ok let me give u a hint
just write the expansion of LHS
2-1tan(x/2)+2-2tan(x/22)+.......+2-ntan(x/2-n) =S
now add cotx on both side, on lhs write
cotx = (1-tan2(x/2))/2tan(x/2)
& go on simplifing, u will get a definite pattern
at last u will get
lim n-> infty 2-ncot(x/2n)
which gives limit as 1/x
so the limit S = (1/x) - cotx
:)