Limits

Lt { ex+(2e)x+(3e)x+...+(ne)x}n/x
x→0--------------------------------------
{n}n/x
a) n!

b) n!en

c)n+logen!

d)en

27 Answers

1
Akand ·

manipal made a mistake in d first step........and his 'a' is n...

62
Lokesh Verma ·

@manipal.. that message was for tapan!

1
Akand ·

k taking ex common out ........we get
en{(1x+2x+...)/n}n/x
by takin 1∞ wala formula
ene{(1x+2x+...)/n-1}n/x
enelogn! (check out mainpals method)
enn!

1
Akand ·

shud i type my solution again?????? im hundred percent sure i hav got d rite answer........k w8 ill type again even if it takes forever ....(hehe just kiddin)

11
Mani Pal Singh ·

then i didn't understood ur 24 post

62
Lokesh Verma ·

@manipal bhai mai question pe shaq nahi kar raha!! (I am not doubtin gthe quesiton!)

21
tapanmast Vora ·

OHHH!!!!
hmmmmm.......... yeah!!!

11
Mani Pal Singh ·

kya aap ques pe shak kar rahe hain
i think ques is correct

62
Lokesh Verma ·

there is a mstake in taking x->0-

that is when you are taking the sum as 1+1+1+...

there is a x in the denominator!

and difference fo 2 terms that tend to infinity is not zero!

11
Mani Pal Singh ·

sir i used ax-1/x = logx
haaan i made a mistake
but the concept is perfect !!!!!!!!!!

21
tapanmast Vora ·

jus a min....
i'll upload ma total workin

**deleted after getting reviewed..... LOL

62
Lokesh Verma ·

I did not understand your log ..

how did u take it

where did the summation go!?

21
tapanmast Vora ·

sir, did u get my mist???

21
tapanmast Vora ·

sum1 pl. help abhirup n myself decipher wer we hav gone wrong [2]

or does the question hav multiple ans [11] LOL [4]

13
Двҥїяuρ now in medical c ·

en...[7]

1
Akand ·

man typing is confusing.........ill tell d method.........i did exactly wat manipal did .......by removing his small mistakes.......

1
Akand ·

en((1x+2x....)/n)n/x
ene(((1x+2x...)/n)-1)n/x
enelogn! ........(using manipals method)

1
sriraghav ·

ya... how a came in??

1
Akand ·

yup i got n!en.......... ill type d solution.....

13
Двҥїяuρ now in medical c ·

tapan.....i did the same .......getting ...en...[2]

1
Akand ·

wat is a in tht???? i think it is n ........so ans is n!

21
tapanmast Vora ·

me too gettin e^n

take log on both sides...
apply limits :

logy = n/x(loge^x) + n/x(logn)-n/x(logn)

logy = n;

y = e^n

1
sriraghav ·

ANS IS B...

1
sriraghav ·

NO !! HERE NO FRACTIONAL PART...

1
Akand ·

are those d fractional part of x???

11
Mani Pal Singh ·

1
sriraghav ·

no

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