m,n belongs to I+ then lim x→0 sinXn/(sinX)m equals to
a. 1 if n<m
b. 0 if n=m
c. n/m
d. 0 if n>m
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1 Answers
1i think it is d
sinxn/(sinx)m
multiply and divide by xn and xmwe have
lim (x→0)xn-m
case 1
if n<m then limit will be ∞ , ie won't exist
case 2
if n=m then x0will be 1 (not zero; as x→0 ,it is not equal to zero)
case 3
if n>m then the limit will be 0
clearly only these cases will exist ,,hence d
