limits

what is limit of (1+ax)^1/xhen x → ∞ ????????????

0

4 Answers

9
Celestine preetham ·

use e^fx form

11
Mani Pal Singh ·

take log u get
log y=1/x log(1+ax)

using l hospital u get

logy=-1/x2 X a/1+ax
so
putting x->∞

we get
logy=0
y=1

3
rocky ·

but answer is e^a

62
Lokesh Verma ·

(1+ax)^1/x

= {(1+ax)^1/(ax)}^a

= e^a

Your Answer

Close [X]